Base | Representation |
---|---|
bin | 110000001101010011000010… |
… | …000110001110100001100001 |
3 | 1000210200220201212122202101220 |
4 | 300031103002012032201201 |
5 | 210242214001113341001 |
6 | 2030532353052445253 |
7 | 62441640536533050 |
oct | 6015230206164141 |
9 | 1023626655582356 |
10 | 212020022012001 |
11 | 61613206091105 |
12 | 1b942a98479829 |
13 | 913c52ca92538 |
14 | 3a4db767b8397 |
15 | 197a1d9b27c36 |
hex | c0d4c218e861 |
212020022012001 has 32 divisors (see below), whose sum is σ = 323587031854080. Its totient is φ = 120963575468736.
The previous prime is 212020022011943. The next prime is 212020022012081. The reversal of 212020022012001 is 100210220020212.
It is not a de Polignac number, because 212020022012001 - 27 = 212020022011873 is a prime.
It is not an unprimeable number, because it can be changed into a prime (212020022012081) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 41549590 + ... + 46372496.
It is an arithmetic number, because the mean of its divisors is an integer number (10112094745440).
Almost surely, 2212020022012001 is an apocalyptic number.
212020022012001 is a gapful number since it is divisible by the number (21) formed by its first and last digit.
It is an amenable number.
212020022012001 is a deficient number, since it is larger than the sum of its proper divisors (111567009842079).
212020022012001 is a wasteful number, since it uses less digits than its factorization.
212020022012001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4826213.
The product of its (nonzero) digits is 64, while the sum is 15.
Adding to 212020022012001 its reverse (100210220020212), we get a palindrome (312230242032213).
The spelling of 212020022012001 in words is "two hundred twelve trillion, twenty billion, twenty-two million, twelve thousand, one".
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