Base | Representation |
---|---|
bin | 11110110110101101101… |
… | …001011111011100101111 |
3 | 21111200221121010120200020 |
4 | 132312231221133130233 |
5 | 234214420021241030 |
6 | 4302022301533223 |
7 | 306121544300433 |
oct | 36665551373457 |
9 | 7450847116606 |
10 | 2120332212015 |
11 | 748256290796 |
12 | 2a2b26b74213 |
13 | 124c3c5172a4 |
14 | 748a5d929c3 |
15 | 3a24c206510 |
hex | 1edada5f72f |
2120332212015 has 16 divisors (see below), whose sum is σ = 3399890620896. Its totient is φ = 1128390819200.
The previous prime is 2120332211951. The next prime is 2120332212023. The reversal of 2120332212015 is 5102122330212.
It is not a de Polignac number, because 2120332212015 - 26 = 2120332211951 is a prime.
It is a super-4 number, since 4×21203322120154 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 153307056 + ... + 153320885.
It is an arithmetic number, because the mean of its divisors is an integer number (212493163806).
Almost surely, 22120332212015 is an apocalyptic number.
2120332212015 is a deficient number, since it is larger than the sum of its proper divisors (1279558408881).
2120332212015 is a wasteful number, since it uses less digits than its factorization.
2120332212015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 306628410.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 2120332212015 its reverse (5102122330212), we get a palindrome (7222454542227).
The spelling of 2120332212015 in words is "two trillion, one hundred twenty billion, three hundred thirty-two million, two hundred twelve thousand, fifteen".
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