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2120343013555 = 51351476337801
BaseRepresentation
bin11110110110101110010…
…010101100100010110011
321111200222100110100121021
4132312232102230202303
5234214430302413210
64302023325240311
7306122035146004
oct36665622544263
97450870410537
102120343013555
11748261399088
122a2b2a703097
13124c41829930
14748a75a51ab
153a24d13bbda
hex1edae4ac8b3

2120343013555 has 16 divisors (see below), whose sum is σ = 2740668394464. Its totient is φ = 1565487302400.

The previous prime is 2120343013553. The next prime is 2120343013601. The reversal of 2120343013555 is 5553103430212.

It is not a de Polignac number, because 2120343013555 - 21 = 2120343013553 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2120343013555.

It is not an unprimeable number, because it can be changed into a prime (2120343013553) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2834346 + ... + 3503455.

It is an arithmetic number, because the mean of its divisors is an integer number (171291774654).

Almost surely, 22120343013555 is an apocalyptic number.

2120343013555 is a deficient number, since it is larger than the sum of its proper divisors (620325380909).

2120343013555 is a wasteful number, since it uses less digits than its factorization.

2120343013555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6342966.

The product of its (nonzero) digits is 54000, while the sum is 34.

Adding to 2120343013555 its reverse (5553103430212), we get a palindrome (7673446443767).

The spelling of 2120343013555 in words is "two trillion, one hundred twenty billion, three hundred forty-three million, thirteen thousand, five hundred fifty-five".

Divisors: 1 5 13 65 5147 25735 66911 334555 6337801 31689005 82391413 411957065 32620661747 163103308735 424068602711 2120343013555