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21204341113 is a prime number
BaseRepresentation
bin10011101111111000…
…001001000101111001
32000201202201010200011
4103233320021011321
5321411302403423
613424030341521
71350314632324
oct235770110571
960652633604
1021204341113
118aa133035a
12413935a8a1
131ccc05c007
1410522257bb
15841862b0d
hex4efe09179

21204341113 has 2 divisors, whose sum is σ = 21204341114. Its totient is φ = 21204341112.

The previous prime is 21204341057. The next prime is 21204341129. The reversal of 21204341113 is 31114340212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14310858384 + 6893482729 = 119628^2 + 83027^2 .

It is a cyclic number.

It is not a de Polignac number, because 21204341113 - 221 = 21202243961 is a prime.

It is not a weakly prime, because it can be changed into another prime (21204371113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10602170556 + 10602170557.

It is an arithmetic number, because the mean of its divisors is an integer number (10602170557).

Almost surely, 221204341113 is an apocalyptic number.

It is an amenable number.

21204341113 is a deficient number, since it is larger than the sum of its proper divisors (1).

21204341113 is an equidigital number, since it uses as much as digits as its factorization.

21204341113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 21204341113 its reverse (31114340212), we get a palindrome (52318681325).

Subtracting 21204341113 from its reverse (31114340212), we obtain a palindrome (9909999099).

The spelling of 21204341113 in words is "twenty-one billion, two hundred four million, three hundred forty-one thousand, one hundred thirteen".