Base | Representation |
---|---|
bin | 110000001101101010011111… |
… | …101011001111001110101001 |
3 | 1000210210022202120102100221011 |
4 | 300031222133223033032221 |
5 | 210243122044331043213 |
6 | 2030552120543143521 |
7 | 62443522040554612 |
oct | 6015523753171651 |
9 | 1023708676370834 |
10 | 212045214315433 |
11 | 61622963523594 |
12 | 1b9479492a4ba1 |
13 | 9141a160b9a65 |
14 | 3a510864dcc09 |
15 | 197abb163403d |
hex | c0da9facf3a9 |
212045214315433 has 2 divisors, whose sum is σ = 212045214315434. Its totient is φ = 212045214315432.
The previous prime is 212045214315391. The next prime is 212045214315439. The reversal of 212045214315433 is 334513412540212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 206682803402089 + 5362410913344 = 14376467^2 + 2315688^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212045214315433 is a prime.
It is not a weakly prime, because it can be changed into another prime (212045214315439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106022607157716 + 106022607157717.
It is an arithmetic number, because the mean of its divisors is an integer number (106022607157717).
Almost surely, 2212045214315433 is an apocalyptic number.
It is an amenable number.
212045214315433 is a deficient number, since it is larger than the sum of its proper divisors (1).
212045214315433 is an equidigital number, since it uses as much as digits as its factorization.
212045214315433 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 345600, while the sum is 40.
Adding to 212045214315433 its reverse (334513412540212), we get a palindrome (546558626855645).
The spelling of 212045214315433 in words is "two hundred twelve trillion, forty-five billion, two hundred fourteen million, three hundred fifteen thousand, four hundred thirty-three".
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