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212045214315433 is a prime number
BaseRepresentation
bin110000001101101010011111…
…101011001111001110101001
31000210210022202120102100221011
4300031222133223033032221
5210243122044331043213
62030552120543143521
762443522040554612
oct6015523753171651
91023708676370834
10212045214315433
1161622963523594
121b9479492a4ba1
139141a160b9a65
143a510864dcc09
15197abb163403d
hexc0da9facf3a9

212045214315433 has 2 divisors, whose sum is σ = 212045214315434. Its totient is φ = 212045214315432.

The previous prime is 212045214315391. The next prime is 212045214315439. The reversal of 212045214315433 is 334513412540212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 206682803402089 + 5362410913344 = 14376467^2 + 2315688^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212045214315433 is a prime.

It is not a weakly prime, because it can be changed into another prime (212045214315439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106022607157716 + 106022607157717.

It is an arithmetic number, because the mean of its divisors is an integer number (106022607157717).

Almost surely, 2212045214315433 is an apocalyptic number.

It is an amenable number.

212045214315433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212045214315433 is an equidigital number, since it uses as much as digits as its factorization.

212045214315433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 345600, while the sum is 40.

Adding to 212045214315433 its reverse (334513412540212), we get a palindrome (546558626855645).

The spelling of 212045214315433 in words is "two hundred twelve trillion, forty-five billion, two hundred fourteen million, three hundred fifteen thousand, four hundred thirty-three".