Base | Representation |
---|---|
bin | 1100010101111101101… |
… | …0000011110000010111 |
3 | 202021100102010120220211 |
4 | 3011133122003300113 |
5 | 11433241320023101 |
6 | 241225530310251 |
7 | 21214616543116 |
oct | 3053732036027 |
9 | 667312116824 |
10 | 212054064151 |
11 | 81a27a99a96 |
12 | 35120588387 |
13 | 16cc5732c07 |
14 | a398d73c7d |
15 | 57b1823c51 |
hex | 315f683c17 |
212054064151 has 8 divisors (see below), whose sum is σ = 217791011504. Its totient is φ = 206317419840.
The previous prime is 212054064133. The next prime is 212054064191. The reversal of 212054064151 is 151460450212.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 212054064151 - 213 = 212054055959 is a prime.
It is a super-3 number, since 3×2120540641513 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212054064191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2675371 + ... + 2753491.
It is an arithmetic number, because the mean of its divisors is an integer number (27223876438).
Almost surely, 2212054064151 is an apocalyptic number.
212054064151 is a deficient number, since it is larger than the sum of its proper divisors (5736947353).
212054064151 is an equidigital number, since it uses as much as digits as its factorization.
212054064151 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 151521.
The product of its (nonzero) digits is 9600, while the sum is 31.
The spelling of 212054064151 in words is "two hundred twelve billion, fifty-four million, sixty-four thousand, one hundred fifty-one".
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