Base | Representation |
---|---|
bin | 1001101001010010111010… |
… | …01000110100100100011101 |
3 | 2210002200000002222202222022 |
4 | 10310221131020310210131 |
5 | 10240001301420214323 |
6 | 113035442430425525 |
7 | 4316244216456056 |
oct | 464513510644435 |
9 | 83080002882868 |
10 | 21210111101213 |
11 | 6838180852121 |
12 | 24667b33622a5 |
13 | bab1495b8568 |
14 | 53480958972d |
15 | 26bacc5784c8 |
hex | 134a5d23491d |
21210111101213 has 16 divisors (see below), whose sum is σ = 23448863819520. Its totient is φ = 19082567513856.
The previous prime is 21210111101203. The next prime is 21210111101227. The reversal of 21210111101213 is 31210111101212.
It is a cyclic number.
It is not a de Polignac number, because 21210111101213 - 24 = 21210111101197 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 21210111101191 and 21210111101200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21210111101203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16359233 + ... + 17608086.
It is an arithmetic number, because the mean of its divisors is an integer number (1465553988720).
Almost surely, 221210111101213 is an apocalyptic number.
21210111101213 is a gapful number since it is divisible by the number (23) formed by its first and last digit.
It is an amenable number.
21210111101213 is a deficient number, since it is larger than the sum of its proper divisors (2238752718307).
21210111101213 is a wasteful number, since it uses less digits than its factorization.
21210111101213 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33968956.
The product of its (nonzero) digits is 24, while the sum is 17.
Adding to 21210111101213 its reverse (31210111101212), we get a palindrome (52420222202425).
Subtracting 21210111101213 from its reverse (31210111101212), we obtain a palindrome (9999999999999).
The spelling of 21210111101213 in words is "twenty-one trillion, two hundred ten billion, one hundred eleven million, one hundred one thousand, two hundred thirteen".
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