2121021409993 has 2 divisors, whose sum is σ = 2121021409994. Its totient is φ = 2121021409992.

The previous prime is 2121021409939. The next prime is 2121021410017. The reversal of 2121021409993 is 3999041201212.

Together with previous prime (2121021409939) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1728309881104 + 392711528889 = 1314652^2 + 626667^2 .

It is a cyclic number.

It is not a de Polignac number, because 2121021409993 - 2¹³ = 2121021401801 is a prime.

It is not a weakly prime, because it can be changed into another prime (2121021409393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060510704996 + 1060510704997.

It is an arithmetic number, because the mean of its divisors is an integer number (1060510704997).

Almost surely, 2^{2121021409993} is an apocalyptic number.

It is an amenable number.

2121021409993 is a deficient number, since it is larger than the sum of its proper divisors (1).

2121021409993 is an equidigital number, since it uses as much as digits as its factorization.

2121021409993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 69984, while the sum is 43.

The spelling of 2121021409993 in words is "two trillion, one hundred twenty-one billion, twenty-one million, four hundred nine thousand, nine hundred ninety-three".