Base | Representation |
---|---|
bin | 110000001110101000110011… |
… | …100111111111010011000001 |
3 | 1000211000201110102011011100012 |
4 | 300032220303213333103001 |
5 | 210300221110434014103 |
6 | 2031042544013434305 |
7 | 62451411044163362 |
oct | 6016506347772301 |
9 | 1024021412134305 |
10 | 212112121001153 |
11 | 6164927760a87a |
12 | 1b95890019b995 |
13 | 914811970a519 |
14 | 3a543d237bb69 |
15 | 197c7ca3bc2d8 |
hex | c0ea339ff4c1 |
212112121001153 has 2 divisors, whose sum is σ = 212112121001154. Its totient is φ = 212112121001152.
The previous prime is 212112121001141. The next prime is 212112121001227. The reversal of 212112121001153 is 351100121211212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 144730235430544 + 67381885570609 = 12030388^2 + 8208647^2 .
It is a cyclic number.
It is not a de Polignac number, because 212112121001153 - 214 = 212112120984769 is a prime.
It is not a weakly prime, because it can be changed into another prime (212112121001113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106056060500576 + 106056060500577.
It is an arithmetic number, because the mean of its divisors is an integer number (106056060500577).
Almost surely, 2212112121001153 is an apocalyptic number.
It is an amenable number.
212112121001153 is a deficient number, since it is larger than the sum of its proper divisors (1).
212112121001153 is an equidigital number, since it uses as much as digits as its factorization.
212112121001153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 212112121001153 its reverse (351100121211212), we get a palindrome (563212242212365).
The spelling of 212112121001153 in words is "two hundred twelve trillion, one hundred twelve billion, one hundred twenty-one million, one thousand, one hundred fifty-three".
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