Base | Representation |
---|---|
bin | 110000001110101000110011… |
… | …101001001000010010000111 |
3 | 1000211000201110102201100102102 |
4 | 300032220303221020102013 |
5 | 210300221111023100403 |
6 | 2031042544024102315 |
7 | 62451411046550063 |
oct | 6016506351102207 |
9 | 1024021412640372 |
10 | 212112121300103 |
11 | 616492777a4442 |
12 | 1b95890030499b |
13 | 91481197b360b |
14 | 3a543d2418aa3 |
15 | 197c7ca42ab88 |
hex | c0ea33a48487 |
212112121300103 has 16 divisors (see below), whose sum is σ = 216872724271104. Its totient is φ = 207361880866560.
The previous prime is 212112121300091. The next prime is 212112121300133. The reversal of 212112121300103 is 301003121211212.
It is a cyclic number.
It is not a de Polignac number, because 212112121300103 - 24 = 212112121300087 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212112121300133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 425926418 + ... + 426424128.
It is an arithmetic number, because the mean of its divisors is an integer number (13554545266944).
Almost surely, 2212112121300103 is an apocalyptic number.
212112121300103 is a deficient number, since it is larger than the sum of its proper divisors (4760602971001).
212112121300103 is an equidigital number, since it uses as much as digits as its factorization.
212112121300103 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 508102.
The product of its (nonzero) digits is 144, while the sum is 20.
Adding to 212112121300103 its reverse (301003121211212), we get a palindrome (513115242511315).
The spelling of 212112121300103 in words is "two hundred twelve trillion, one hundred twelve billion, one hundred twenty-one million, three hundred thousand, one hundred three".
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