Base | Representation |
---|---|
bin | 1001101001010101001101… |
… | …01001010001000100000110 |
3 | 2210002210012001112222002020 |
4 | 10310222212221101010012 |
5 | 10240011313122441202 |
6 | 113040205043224010 |
7 | 4316316613035051 |
oct | 464524651210406 |
9 | 83083161488066 |
10 | 21211344343302 |
11 | 68387539a3163 |
12 | 2466a98378006 |
13 | bab2b4c4b5c9 |
14 | 5348c528da98 |
15 | 26bb5097d5bc |
hex | 134aa6a51106 |
21211344343302 has 16 divisors (see below), whose sum is σ = 43569247840752. Its totient is φ = 6879354922080.
The previous prime is 21211344343153. The next prime is 21211344343303. The reversal of 21211344343302 is 20334344311212.
It is a super-2 number, since 2×212113443433022 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21211344343303) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47773297849 + ... + 47773298292.
It is an arithmetic number, because the mean of its divisors is an integer number (2723077990047).
Almost surely, 221211344343302 is an apocalyptic number.
21211344343302 is an abundant number, since it is smaller than the sum of its proper divisors (22357903497450).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
21211344343302 is a wasteful number, since it uses less digits than its factorization.
21211344343302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95546596183.
The product of its (nonzero) digits is 41472, while the sum is 33.
Adding to 21211344343302 its reverse (20334344311212), we get a palindrome (41545688654514).
The spelling of 21211344343302 in words is "twenty-one trillion, two hundred eleven billion, three hundred forty-four million, three hundred forty-three thousand, three hundred two".
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