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212121010212002 = 2106060505106001
BaseRepresentation
bin110000001110110001000101…
…011101101000110010100010
31000211001120101220202212012122
4300032301011131220302202
5210300342312103241002
62031051014040224242
762452144243215113
oct6016610535506242
91024046356685178
10212121010212002
1161652019310521
121b95a58116b082
139148c0523a1b8
143a549d6b9420a
15197cb4a9b26a2
hexc0ec45768ca2

212121010212002 has 4 divisors (see below), whose sum is σ = 318181515318006. Its totient is φ = 106060505106000.

The previous prime is 212121010211989. The next prime is 212121010212019. The reversal of 212121010212002 is 200212010121212.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 108382487097481 + 103738523114521 = 10410691^2 + 10185211^2 .

It is a super-3 number, since 3×2121210102120023 (a number of 44 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 53030252552999 + ... + 53030252553002.

Almost surely, 2212121010212002 is an apocalyptic number.

212121010212002 is a deficient number, since it is larger than the sum of its proper divisors (106060505106004).

212121010212002 is a wasteful number, since it uses less digits than its factorization.

212121010212002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 106060505106003.

The product of its (nonzero) digits is 64, while the sum is 17.

Adding to 212121010212002 its reverse (200212010121212), we get a palindrome (412333020333214).

The spelling of 212121010212002 in words is "two hundred twelve trillion, one hundred twenty-one billion, ten million, two hundred twelve thousand, two".

Divisors: 1 2 106060505106001 212121010212002