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21212131132 = 2241129342263
BaseRepresentation
bin10011110000010101…
…110110111100111100
32000202022100220120101
4103300111312330330
5321420301144012
613424505330444
71350441065623
oct236025667474
960668326511
1021212131132
118aa5771095
12413ba96a24
1320008589aa
1410532926ba
158423a0d57
hex4f0576f3c

21212131132 has 12 divisors (see below), whose sum is σ = 38026625616. Its totient is φ = 10347380960.

The previous prime is 21212131111. The next prime is 21212131153. The reversal of 21212131132 is 23113121212.

It is an interprime number because it is at equal distance from previous prime (21212131111) and next prime (21212131153).

It is a super-3 number, since 3×212121311323 (a number of 32 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 64670968 + ... + 64671295.

It is an arithmetic number, because the mean of its divisors is an integer number (3168885468).

Almost surely, 221212131132 is an apocalyptic number.

It is an amenable number.

21212131132 is a deficient number, since it is larger than the sum of its proper divisors (16814494484).

21212131132 is a wasteful number, since it uses less digits than its factorization.

21212131132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 129342308 (or 129342306 counting only the distinct ones).

The product of its digits is 144, while the sum is 19.

Adding to 21212131132 its reverse (23113121212), we get a palindrome (44325252344).

It can be divided in two parts, 212121 and 31132, that added together give a triangular number (243253 = T697).

The spelling of 21212131132 in words is "twenty-one billion, two hundred twelve million, one hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 4 41 82 164 129342263 258684526 517369052 5303032783 10606065566 21212131132