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212122112121041 is a prime number
BaseRepresentation
bin110000001110110010000111…
…001001000101100011010001
31000211001200020201012122020112
4300032302013021011203101
5210300402041200333131
62031051315242051105
762452213453251653
oct6016620711054321
91024050221178215
10212122112121041
116165253430a051
121b95a82a1a9a95
13914904c608a95
143a54a9d26c6d3
15197cbb25c402b
hexc0ec872458d1

212122112121041 has 2 divisors, whose sum is σ = 212122112121042. Its totient is φ = 212122112121040.

The previous prime is 212122112120959. The next prime is 212122112121113. The reversal of 212122112121041 is 140121211221212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 189778727040400 + 22343385080641 = 13776020^2 + 4726879^2 .

It is a cyclic number.

It is not a de Polignac number, because 212122112121041 - 218 = 212122111858897 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212122112120998 and 212122112121016.

It is not a weakly prime, because it can be changed into another prime (212122112121841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106061056060520 + 106061056060521.

It is an arithmetic number, because the mean of its divisors is an integer number (106061056060521).

Almost surely, 2212122112121041 is an apocalyptic number.

It is an amenable number.

212122112121041 is a deficient number, since it is larger than the sum of its proper divisors (1).

212122112121041 is an equidigital number, since it uses as much as digits as its factorization.

212122112121041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 23.

Adding to 212122112121041 its reverse (140121211221212), we get a palindrome (352243323342253).

The spelling of 212122112121041 in words is "two hundred twelve trillion, one hundred twenty-two billion, one hundred twelve million, one hundred twenty-one thousand, forty-one".