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212124433 is a prime number
BaseRepresentation
bin11001010010011…
…00001100010001
3112210011001000111
430221030030101
5413300440213
633014321321
75154012403
oct1451141421
9483131014
10212124433
11a9814254
125b059241
1334c40b21
142025ab73
1513951a3d
hexca4c311

212124433 has 2 divisors, whose sum is σ = 212124434. Its totient is φ = 212124432.

The previous prime is 212124421. The next prime is 212124443. The reversal of 212124433 is 334421212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 154181889 + 57942544 = 12417^2 + 7612^2 .

It is a cyclic number.

It is not a de Polignac number, because 212124433 - 29 = 212123921 is a prime.

It is not a weakly prime, because it can be changed into another prime (212124403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106062216 + 106062217.

It is an arithmetic number, because the mean of its divisors is an integer number (106062217).

Almost surely, 2212124433 is an apocalyptic number.

It is an amenable number.

212124433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212124433 is an equidigital number, since it uses as much as digits as its factorization.

212124433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1152, while the sum is 22.

The square root of 212124433 is about 14564.4921984943. The cubic root of 212124433 is about 596.3898334330.

Adding to 212124433 its reverse (334421212), we get a palindrome (546545645).

The spelling of 212124433 in words is "two hundred twelve million, one hundred twenty-four thousand, four hundred thirty-three".