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212130315335 = 579537038773
BaseRepresentation
bin1100010110001111110…
…0111011110001000111
3202021112201121112212202
43011203330323301013
511433420330042320
6241241252505115
721216533633561
oct3054374736107
9667481545782
10212130315335
1181a6703a6a4
123514201b19b
131700847cb63
14a3a5142331
1557b8386b75
hex3163f3bc47

212130315335 has 8 divisors (see below), whose sum is σ = 257778611520. Its totient is φ = 167556096864.

The previous prime is 212130315269. The next prime is 212130315367. The reversal of 212130315335 is 533513031212.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-212130315335 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 212130315298 and 212130315307.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 268518992 + ... + 268519781.

It is an arithmetic number, because the mean of its divisors is an integer number (32222326440).

Almost surely, 2212130315335 is an apocalyptic number.

212130315335 is a deficient number, since it is larger than the sum of its proper divisors (45648296185).

212130315335 is an equidigital number, since it uses as much as digits as its factorization.

212130315335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 537038857.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 212130315335 its reverse (533513031212), we get a palindrome (745643346547).

The spelling of 212130315335 in words is "two hundred twelve billion, one hundred thirty million, three hundred fifteen thousand, three hundred thirty-five".

Divisors: 1 5 79 395 537038773 2685193865 42426063067 212130315335