Base | Representation |
---|---|
bin | 11110110111101001000… |
… | …111110000000010101011 |
3 | 21111210112010122110112101 |
4 | 132313221013300002223 |
5 | 234223440440000133 |
6 | 4302305303554231 |
7 | 306155351326432 |
oct | 36675107600253 |
9 | 7453463573471 |
10 | 2121330000043 |
11 | 7487185336a1 |
12 | 2a316515b977 |
13 | 12506b15b6c7 |
14 | 7495c6c6119 |
15 | 3a2a9aec37d |
hex | 1ede91f00ab |
2121330000043 has 2 divisors, whose sum is σ = 2121330000044. Its totient is φ = 2121330000042.
The previous prime is 2121330000001. The next prime is 2121330000061. The reversal of 2121330000043 is 3400000331212.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2121330000043 - 217 = 2121329868971 is a prime.
It is not a weakly prime, because it can be changed into another prime (2121330000343) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1060665000021 + 1060665000022.
It is an arithmetic number, because the mean of its divisors is an integer number (1060665000022).
Almost surely, 22121330000043 is an apocalyptic number.
2121330000043 is a deficient number, since it is larger than the sum of its proper divisors (1).
2121330000043 is an equidigital number, since it uses as much as digits as its factorization.
2121330000043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 2121330000043 its reverse (3400000331212), we get a palindrome (5521330331255).
The spelling of 2121330000043 in words is "two trillion, one hundred twenty-one billion, three hundred thirty million, forty-three", and thus it is an aban number.
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