| Base | Representation |
|---|---|
| bin | 1100010110010000011… |
| … | …1101000110010110000 |
| 3 | 202021112220220002210200 |
| 4 | 3011210013220302300 |
| 5 | 11433422034334300 |
| 6 | 241241432555200 |
| 7 | 21216566531130 |
| oct | 3054407506260 |
| 9 | 667486802720 |
| 10 | 212133121200 |
| 11 | 81a686867a0 |
| 12 | 35142b52b00 |
| 13 | 17008c23030 |
| 14 | a3a5672ac0 |
| 15 | 57b873d200 |
| hex | 31641e8cb0 |
212133121200 has 2160 divisors, whose sum is σ = 1039471969536. Its totient is φ = 38668492800.
The previous prime is 212133121183. The next prime is 212133121201. The reversal of 212133121200 is 2121331212.
212133121200 is a `hidden beast` number, since 2 + 121 + 331 + 212 + 0 + 0 = 666.
It is a super-2 number, since 2×2121331212002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212133121201) by changing a digit.
It is a polite number, since it can be written in 431 ways as a sum of consecutive naturals, for example, 4933328379 + ... + 4933328421.
Almost surely, 2212133121200 is an apocalyptic number.
212133121200 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 212133121200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (519735984768).
212133121200 is an abundant number, since it is smaller than the sum of its proper divisors (827338848336).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212133121200 is a wasteful number, since it uses less digits than its factorization.
212133121200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 172 (or 121 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 212133121200 its reverse (2121331212), we get a palindrome (214254452412).
212133121200 divided by its reverse (2121331212) gives a square (100 = 102).
It can be divided in two parts, 212133 and 121200, that added together give a palindrome (333333).
The spelling of 212133121200 in words is "two hundred twelve billion, one hundred thirty-three million, one hundred twenty-one thousand, two hundred".
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