Search a number
-
+
2121354331511 = 61131049933053
BaseRepresentation
bin11110110111101010100…
…100100100010101110111
321111210120211102122000212
4132313222210210111313
5234224013202102021
64302311533300035
7306156065205602
oct36675244442567
97453524378025
102121354331511
11748730242248
122a317133461b
131250731ca51c
1474961a1b339
153a2abd0685b
hex1edea924577

2121354331511 has 8 divisors (see below), whose sum is σ = 2121967638000. Its totient is φ = 2120741124352.

The previous prime is 2121354331493. The next prime is 2121354331549. The reversal of 2121354331511 is 1151334531212.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2121354331511 - 238 = 1846476424567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2121354331711) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 64163861 + ... + 64196913.

It is an arithmetic number, because the mean of its divisors is an integer number (265245954750).

Almost surely, 22121354331511 is an apocalyptic number.

2121354331511 is a deficient number, since it is larger than the sum of its proper divisors (613306489).

2121354331511 is a wasteful number, since it uses less digits than its factorization.

2121354331511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 49665.

The product of its digits is 10800, while the sum is 32.

Adding to 2121354331511 its reverse (1151334531212), we get a palindrome (3272688862723).

The spelling of 2121354331511 in words is "two trillion, one hundred twenty-one billion, three hundred fifty-four million, three hundred thirty-one thousand, five hundred eleven".

Divisors: 1 6113 10499 33053 64180387 202052989 347023447 2121354331511