Base | Representation |
---|---|
bin | 10011110000011011… |
… | …011101001011100001 |
3 | 2000202102010110022212 |
4 | 103300123131023201 |
5 | 321421140122213 |
6 | 13425001011505 |
7 | 1350456416516 |
oct | 236033351341 |
9 | 60672113285 |
10 | 21213598433 |
11 | 8aa6583535 |
12 | 4140483b95 |
13 | 2000c50811 |
14 | 105355530d |
15 | 8425909a8 |
hex | 4f06dd2e1 |
21213598433 has 2 divisors, whose sum is σ = 21213598434. Its totient is φ = 21213598432.
The previous prime is 21213598387. The next prime is 21213598453. The reversal of 21213598433 is 33489531212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 18205295329 + 3008303104 = 134927^2 + 54848^2 .
It is a cyclic number.
It is not a de Polignac number, because 21213598433 - 28 = 21213598177 is a prime.
It is not a weakly prime, because it can be changed into another prime (21213598453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10606799216 + 10606799217.
It is an arithmetic number, because the mean of its divisors is an integer number (10606799217).
Almost surely, 221213598433 is an apocalyptic number.
It is an amenable number.
21213598433 is a deficient number, since it is larger than the sum of its proper divisors (1).
21213598433 is an equidigital number, since it uses as much as digits as its factorization.
21213598433 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 41.
The spelling of 21213598433 in words is "twenty-one billion, two hundred thirteen million, five hundred ninety-eight thousand, four hundred thirty-three".
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