Base | Representation |
---|---|
bin | 11110110111101101011… |
… | …100000101110110010111 |
3 | 21111210201011221211222220 |
4 | 132313231130011312113 |
5 | 234224113011103421 |
6 | 4302320412353423 |
7 | 306160221141042 |
oct | 36675534056627 |
9 | 7453634854886 |
10 | 2121402441111 |
11 | 748755411748 |
12 | 2a3185475873 |
13 | 125080173345 |
14 | 74968181c59 |
15 | 3a2b115b3c6 |
hex | 1eded705d97 |
2121402441111 has 4 divisors (see below), whose sum is σ = 2828536588152. Its totient is φ = 1414268294072.
The previous prime is 2121402441071. The next prime is 2121402441187. The reversal of 2121402441111 is 1111442041212.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2121402441111 - 211 = 2121402439063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2121402431111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 353567073516 + ... + 353567073521.
It is an arithmetic number, because the mean of its divisors is an integer number (707134147038).
Almost surely, 22121402441111 is an apocalyptic number.
2121402441111 is a deficient number, since it is larger than the sum of its proper divisors (707134147041).
2121402441111 is an equidigital number, since it uses as much as digits as its factorization.
2121402441111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 707134147040.
The product of its (nonzero) digits is 512, while the sum is 24.
Adding to 2121402441111 its reverse (1111442041212), we get a palindrome (3232844482323).
The spelling of 2121402441111 in words is "two trillion, one hundred twenty-one billion, four hundred two million, four hundred forty-one thousand, one hundred eleven".
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