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21214040434121 is a prime number
BaseRepresentation
bin1001101001011010001110…
…10110000010010111001001
32210010001010221201120101202
410310231013112002113021
510240032323322342441
6113041332353553545
74316443461320123
oct464550726022711
983101127646352
1021214040434121
11683990785a097
12246750b2758b5
13bab624696912
14534a9d386213
1526bc5c4e019b
hex134b475825c9

21214040434121 has 2 divisors, whose sum is σ = 21214040434122. Its totient is φ = 21214040434120.

The previous prime is 21214040434079. The next prime is 21214040434133. The reversal of 21214040434121 is 12143404041212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20300746753225 + 913293680896 = 4505635^2 + 955664^2 .

It is a cyclic number.

It is not a de Polignac number, because 21214040434121 - 222 = 21214036239817 is a prime.

It is a super-2 number, since 2×212140404341212 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (21214040634121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607020217060 + 10607020217061.

It is an arithmetic number, because the mean of its divisors is an integer number (10607020217061).

Almost surely, 221214040434121 is an apocalyptic number.

It is an amenable number.

21214040434121 is a deficient number, since it is larger than the sum of its proper divisors (1).

21214040434121 is an equidigital number, since it uses as much as digits as its factorization.

21214040434121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6144, while the sum is 29.

Adding to 21214040434121 its reverse (12143404041212), we get a palindrome (33357444475333).

The spelling of 21214040434121 in words is "twenty-one trillion, two hundred fourteen billion, forty million, four hundred thirty-four thousand, one hundred twenty-one".