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21214142133 = 37071380711
BaseRepresentation
bin10011110000011101…
…100001111010110101
32000202110011002010220
4103300131201322311
5321421310022013
613425020404553
71350464142612
oct236035417265
960673132126
1021214142133
118aa6914a78
1241406a6759
1320010b1132
141053657509
1584264bb23
hex4f0761eb5

21214142133 has 4 divisors (see below), whose sum is σ = 28285522848. Its totient is φ = 14142761420.

The previous prime is 21214142119. The next prime is 21214142153. The reversal of 21214142133 is 33124141212.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21214142133 - 29 = 21214141621 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21214142153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3535690353 + ... + 3535690358.

It is an arithmetic number, because the mean of its divisors is an integer number (7071380712).

Almost surely, 221214142133 is an apocalyptic number.

It is an amenable number.

21214142133 is a deficient number, since it is larger than the sum of its proper divisors (7071380715).

21214142133 is an equidigital number, since it uses as much as digits as its factorization.

21214142133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7071380714.

The product of its digits is 1152, while the sum is 24.

Adding to 21214142133 its reverse (33124141212), we get a palindrome (54338283345).

The spelling of 21214142133 in words is "twenty-one billion, two hundred fourteen million, one hundred forty-two thousand, one hundred thirty-three".

Divisors: 1 3 7071380711 21214142133