Search a number
-
+
212142111030433 is a prime number
BaseRepresentation
bin110000001111000100101111…
…001010110111110010100001
31000211010120212110200111110101
4300033010233022313302201
5210301214020410433213
62031104423532102401
762453522163214153
oct6017045712676241
91024116773614411
10212142111030433
116165aa67163741
121b96268b904a01
13914abb89c118c
143a55a3934cad3
15197d4831c6bdd
hexc0f12f2b7ca1

212142111030433 has 2 divisors, whose sum is σ = 212142111030434. Its totient is φ = 212142111030432.

The previous prime is 212142111030427. The next prime is 212142111030449. The reversal of 212142111030433 is 334030111241212.

212142111030433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 135822894958864 + 76319216071569 = 11654308^2 + 8736087^2 .

It is a cyclic number.

It is not a de Polignac number, because 212142111030433 - 221 = 212142108933281 is a prime.

It is not a weakly prime, because it can be changed into another prime (212142111030413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106071055515216 + 106071055515217.

It is an arithmetic number, because the mean of its divisors is an integer number (106071055515217).

Almost surely, 2212142111030433 is an apocalyptic number.

It is an amenable number.

212142111030433 is a deficient number, since it is larger than the sum of its proper divisors (1).

212142111030433 is an equidigital number, since it uses as much as digits as its factorization.

212142111030433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3456, while the sum is 28.

Adding to 212142111030433 its reverse (334030111241212), we get a palindrome (546172222271645).

The spelling of 212142111030433 in words is "two hundred twelve trillion, one hundred forty-two billion, one hundred eleven million, thirty thousand, four hundred thirty-three".