Base | Representation |
---|---|
bin | 110000001111000101110110… |
… | …110001000011010000000011 |
3 | 1000211010200222011221022101211 |
4 | 300033011312301003100003 |
5 | 210301224000412034222 |
6 | 2031105143041510551 |
7 | 62453564020162054 |
oct | 6017056661032003 |
9 | 1024120864838354 |
10 | 212143312221187 |
11 | 61660523203076 |
12 | 1b962966042457 |
13 | 914b04a811639 |
14 | 3a55b10aac72b |
15 | 197d50389a277 |
hex | c0f176c43403 |
212143312221187 has 2 divisors, whose sum is σ = 212143312221188. Its totient is φ = 212143312221186.
The previous prime is 212143312221143. The next prime is 212143312221223. The reversal of 212143312221187 is 781122213341212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212143312221187 is a prime.
It is a super-2 number, since 2×2121433122211872 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (212143312224187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106071656110593 + 106071656110594.
It is an arithmetic number, because the mean of its divisors is an integer number (106071656110594).
Almost surely, 2212143312221187 is an apocalyptic number.
212143312221187 is a deficient number, since it is larger than the sum of its proper divisors (1).
212143312221187 is an equidigital number, since it uses as much as digits as its factorization.
212143312221187 is an evil number, because the sum of its binary digits is even.
The product of its digits is 64512, while the sum is 40.
Adding to 212143312221187 its reverse (781122213341212), we get a palindrome (993265525562399).
The spelling of 212143312221187 in words is "two hundred twelve trillion, one hundred forty-three billion, three hundred twelve million, two hundred twenty-one thousand, one hundred eighty-seven".
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