Base | Representation |
---|---|
bin | 1001101001011011001011… |
… | …11110101101101111010011 |
3 | 2210010002110202212110021212 |
4 | 10310231211332231233103 |
5 | 10240034401412222120 |
6 | 113041455354210335 |
7 | 4316462302140623 |
oct | 464554576555723 |
9 | 83102422773255 |
10 | 21214554414035 |
11 | 683a0509a4884 |
12 | 24676334239ab |
13 | bab6a7004c48 |
14 | 534b0b73a883 |
15 | 26bc8c6ba6c5 |
hex | 134b65fadbd3 |
21214554414035 has 8 divisors (see below), whose sum is σ = 26564311614240. Its totient is φ = 16233745986304.
The previous prime is 21214554414023. The next prime is 21214554414041. The reversal of 21214554414035 is 53041445541212.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 21214554414035 - 214 = 21214554397651 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21214554413983 and 21214554414001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 92237192990 + ... + 92237193219.
It is an arithmetic number, because the mean of its divisors is an integer number (3320538951780).
Almost surely, 221214554414035 is an apocalyptic number.
21214554414035 is a deficient number, since it is larger than the sum of its proper divisors (5349757200205).
21214554414035 is a wasteful number, since it uses less digits than its factorization.
21214554414035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 184474386237.
The product of its (nonzero) digits is 384000, while the sum is 41.
Adding to 21214554414035 its reverse (53041445541212), we get a palindrome (74255999955247).
The spelling of 21214554414035 in words is "twenty-one trillion, two hundred fourteen billion, five hundred fifty-four million, four hundred fourteen thousand, thirty-five".
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