21214554414041 has 2 divisors, whose sum is σ = 21214554414042. Its totient is φ = 21214554414040.

The previous prime is 21214554414023. The next prime is 21214554414043. The reversal of 21214554414041 is 14041445541212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 18180809098816 + 3033745315225 = 4263896^2 + 1741765^2 .

It is a cyclic number.

It is not a de Polignac number, because 21214554414041 - 2³⁸ = 20939676507097 is a prime.

Together with 21214554414043, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 21214554413986 and 21214554414004.

It is not a weakly prime, because it can be changed into another prime (21214554414043) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10607277207020 + 10607277207021.

It is an arithmetic number, because the mean of its divisors is an integer number (10607277207021).

Almost surely, 2^{21214554414041} is an apocalyptic number.

It is an amenable number.

21214554414041 is a deficient number, since it is larger than the sum of its proper divisors (1).

21214554414041 is an equidigital number, since it uses as much as digits as its factorization.

21214554414041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 102400, while the sum is 38.

Adding to 21214554414041 its reverse (14041445541212), we get a palindrome (35255999955253).

The spelling of 21214554414041 in words is "twenty-one trillion, two hundred fourteen billion, five hundred fifty-four million, four hundred fourteen thousand, forty-one".