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212190749094953 is a prime number
BaseRepresentation
bin110000001111110010000010…
…001110010111010000101001
31000211022020102010210011211102
4300033302002032113100221
5210303013123232014303
62031143030122411145
762460163400021426
oct6017620216272051
91024266363704742
10212190749094953
1161679656076482
121b96bba4660ab5
13915266a54c005
143a58130c38d4d
15197e87d1e5288
hexc0fc82397429

212190749094953 has 2 divisors, whose sum is σ = 212190749094954. Its totient is φ = 212190749094952.

The previous prime is 212190749094941. The next prime is 212190749094979. The reversal of 212190749094953 is 359490947091212.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 208046381458969 + 4144367635984 = 14423813^2 + 2035772^2 .

It is a cyclic number.

It is not a de Polignac number, because 212190749094953 - 224 = 212190732317737 is a prime.

It is a super-2 number, since 2×2121907490949532 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 212190749094953.

It is not a weakly prime, because it can be changed into another prime (212190749091953) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106095374547476 + 106095374547477.

It is an arithmetic number, because the mean of its divisors is an integer number (106095374547477).

Almost surely, 2212190749094953 is an apocalyptic number.

It is an amenable number.

212190749094953 is a deficient number, since it is larger than the sum of its proper divisors (1).

212190749094953 is an equidigital number, since it uses as much as digits as its factorization.

212190749094953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 44089920, while the sum is 65.

The spelling of 212190749094953 in words is "two hundred twelve trillion, one hundred ninety billion, seven hundred forty-nine million, ninety-four thousand, nine hundred fifty-three".