Base | Representation |
---|---|
bin | 110000001111111011110001… |
… | …110011010111010011001011 |
3 | 1000211100020102020201000120112 |
4 | 300033323301303113103023 |
5 | 210303201040004000021 |
6 | 2031151520205344535 |
7 | 62461013553525362 |
oct | 6017736163272313 |
9 | 1024306366630515 |
10 | 212201211000011 |
11 | 61683034598602 |
12 | 1b97202426814b |
13 | 9153646b43b8c |
14 | 3a588444787d9 |
15 | 197ec918e3d5b |
hex | c0fef1cd74cb |
212201211000011 has 2 divisors, whose sum is σ = 212201211000012. Its totient is φ = 212201211000010.
The previous prime is 212201211000001. The next prime is 212201211000019. The reversal of 212201211000011 is 110000112102212.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212201211000011 is a prime.
It is a Sophie Germain prime.
It is a self number, because there is not a number n which added to its sum of digits gives 212201211000011.
It is not a weakly prime, because it can be changed into another prime (212201211000019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106100605500005 + 106100605500006.
It is an arithmetic number, because the mean of its divisors is an integer number (106100605500006).
Almost surely, 2212201211000011 is an apocalyptic number.
212201211000011 is a deficient number, since it is larger than the sum of its proper divisors (1).
212201211000011 is an equidigital number, since it uses as much as digits as its factorization.
212201211000011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 212201211000011 its reverse (110000112102212), we get a palindrome (322201323102223).
The spelling of 212201211000011 in words is "two hundred twelve trillion, two hundred one billion, two hundred eleven million, eleven", and thus it is an aban number.
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