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212221221000097 is a prime number
BaseRepresentation
bin110000010000001110011010…
…011111011101001110100001
31000211102011001210001100100211
4300100032122133131032201
5210304013030034000342
62031205025533214121
762462322456652141
oct6020163237351641
91024364053040324
10212221221000097
1161690572727861
121b975a89631341
1391554b561040a
143a597c1c04921
151980563487c17
hexc1039a7dd3a1

212221221000097 has 2 divisors, whose sum is σ = 212221221000098. Its totient is φ = 212221221000096.

The previous prime is 212221221000017. The next prime is 212221221000137. The reversal of 212221221000097 is 790000122122212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 183528903776656 + 28692317223441 = 13547284^2 + 5356521^2 .

It is a cyclic number.

It is not a de Polignac number, because 212221221000097 - 211 = 212221220998049 is a prime.

It is not a weakly prime, because it can be changed into another prime (212221221000017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106110610500048 + 106110610500049.

It is an arithmetic number, because the mean of its divisors is an integer number (106110610500049).

Almost surely, 2212221221000097 is an apocalyptic number.

It is an amenable number.

212221221000097 is a deficient number, since it is larger than the sum of its proper divisors (1).

212221221000097 is an equidigital number, since it uses as much as digits as its factorization.

212221221000097 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4032, while the sum is 31.

The spelling of 212221221000097 in words is "two hundred twelve trillion, two hundred twenty-one billion, two hundred twenty-one million, ninety-seven", and thus it is an aban number.