Base | Representation |
---|---|
bin | 110000010000010000010111… |
… | …001001001011001101101011 |
3 | 1000211102100110112012221210122 |
4 | 300100100113021023031223 |
5 | 210304031320422424042 |
6 | 2031210013241233455 |
7 | 62462425342546664 |
oct | 6020202711131553 |
9 | 1024370415187718 |
10 | 212223312311147 |
11 | 616914461707a5 |
12 | 1b976371a9288b |
13 | 9155759978387 |
14 | 3a5993d86c36b |
15 | 1980636d857d2 |
hex | c1041724b36b |
212223312311147 has 2 divisors, whose sum is σ = 212223312311148. Its totient is φ = 212223312311146.
The previous prime is 212223312311137. The next prime is 212223312311317. The reversal of 212223312311147 is 741113213322212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212223312311147 - 212 = 212223312307051 is a prime.
It is not a weakly prime, because it can be changed into another prime (212223312311117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106111656155573 + 106111656155574.
It is an arithmetic number, because the mean of its divisors is an integer number (106111656155574).
Almost surely, 2212223312311147 is an apocalyptic number.
212223312311147 is a deficient number, since it is larger than the sum of its proper divisors (1).
212223312311147 is an equidigital number, since it uses as much as digits as its factorization.
212223312311147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 24192, while the sum is 35.
Adding to 212223312311147 its reverse (741113213322212), we get a palindrome (953336525633359).
The spelling of 212223312311147 in words is "two hundred twelve trillion, two hundred twenty-three billion, three hundred twelve million, three hundred eleven thousand, one hundred forty-seven".
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