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2122301300131 is a prime number
BaseRepresentation
bin11110111000100011000…
…000111101110110100011
321111220000211022121202201
4132320203000331312203
5234232433113101011
64302545522154031
7306221414255215
oct36704300756643
97456024277681
102122301300131
11749076834841
122a33964b2917
1312519445a59c
1474a116c25b5
153a31500ecc1
hex1ee2303dda3

2122301300131 has 2 divisors, whose sum is σ = 2122301300132. Its totient is φ = 2122301300130.

The previous prime is 2122301300111. The next prime is 2122301300219. The reversal of 2122301300131 is 1310031032212.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2122301300131 is a prime.

It is a super-2 number, since 2×21223013001312 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2122301300099 and 2122301300108.

It is not a weakly prime, because it can be changed into another prime (2122301300111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061150650065 + 1061150650066.

It is an arithmetic number, because the mean of its divisors is an integer number (1061150650066).

Almost surely, 22122301300131 is an apocalyptic number.

2122301300131 is a deficient number, since it is larger than the sum of its proper divisors (1).

2122301300131 is an equidigital number, since it uses as much as digits as its factorization.

2122301300131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 2122301300131 its reverse (1310031032212), we get a palindrome (3432332332343).

The spelling of 2122301300131 in words is "two trillion, one hundred twenty-two billion, three hundred one million, three hundred thousand, one hundred thirty-one".