Base | Representation |
---|---|
bin | 11110111000100011000… |
… | …000111101110110100011 |
3 | 21111220000211022121202201 |
4 | 132320203000331312203 |
5 | 234232433113101011 |
6 | 4302545522154031 |
7 | 306221414255215 |
oct | 36704300756643 |
9 | 7456024277681 |
10 | 2122301300131 |
11 | 749076834841 |
12 | 2a33964b2917 |
13 | 12519445a59c |
14 | 74a116c25b5 |
15 | 3a31500ecc1 |
hex | 1ee2303dda3 |
2122301300131 has 2 divisors, whose sum is σ = 2122301300132. Its totient is φ = 2122301300130.
The previous prime is 2122301300111. The next prime is 2122301300219. The reversal of 2122301300131 is 1310031032212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2122301300131 is a prime.
It is a super-2 number, since 2×21223013001312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2122301300099 and 2122301300108.
It is not a weakly prime, because it can be changed into another prime (2122301300111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061150650065 + 1061150650066.
It is an arithmetic number, because the mean of its divisors is an integer number (1061150650066).
Almost surely, 22122301300131 is an apocalyptic number.
2122301300131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122301300131 is an equidigital number, since it uses as much as digits as its factorization.
2122301300131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 2122301300131 its reverse (1310031032212), we get a palindrome (3432332332343).
The spelling of 2122301300131 in words is "two trillion, one hundred twenty-two billion, three hundred one million, three hundred thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •