Base | Representation |
---|---|
bin | 110000010000011111111100… |
… | …001100101000110011010001 |
3 | 1000211110221122022111211111112 |
4 | 300100133330030220303101 |
5 | 210304320100231244441 |
6 | 2031221421200023105 |
7 | 62463560022462542 |
oct | 6020377414506321 |
9 | 1024427568454445 |
10 | 212240040103121 |
11 | 6169854a608468 |
12 | 1b979660001a95 |
13 | 91571c4451934 |
14 | 3a5a6893304c9 |
15 | 1980cb56dd4eb |
hex | c107fc328cd1 |
212240040103121 has 2 divisors, whose sum is σ = 212240040103122. Its totient is φ = 212240040103120.
The previous prime is 212240040103099. The next prime is 212240040103181. The reversal of 212240040103121 is 121301040042212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 191480944976896 + 20759095126225 = 13837664^2 + 4556215^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-212240040103121 is a prime.
It is not a weakly prime, because it can be changed into another prime (212240040103181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106120020051560 + 106120020051561.
It is an arithmetic number, because the mean of its divisors is an integer number (106120020051561).
Almost surely, 2212240040103121 is an apocalyptic number.
It is an amenable number.
212240040103121 is a deficient number, since it is larger than the sum of its proper divisors (1).
212240040103121 is an equidigital number, since it uses as much as digits as its factorization.
212240040103121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 212240040103121 its reverse (121301040042212), we get a palindrome (333541080145333).
The spelling of 212240040103121 in words is "two hundred twelve trillion, two hundred forty billion, forty million, one hundred three thousand, one hundred twenty-one".
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