Base | Representation |
---|---|
bin | 11110111000101100000… |
… | …110001001101010000011 |
3 | 21111220102110000000012001 |
4 | 132320230012021222003 |
5 | 234233241113413042 |
6 | 4303013003444431 |
7 | 306225244251061 |
oct | 36705406115203 |
9 | 7456373000161 |
10 | 2122453654147 |
11 | 749144834652 |
12 | 2a3419526717 |
13 | 1251b9ba1aa8 |
14 | 74a27a21031 |
15 | 3a3235a6bb7 |
hex | 1ee2c189a83 |
2122453654147 has 2 divisors, whose sum is σ = 2122453654148. Its totient is φ = 2122453654146.
The previous prime is 2122453654109. The next prime is 2122453654187. The reversal of 2122453654147 is 7414563542212.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2122453654147 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2122453654097 and 2122453654106.
It is not a weakly prime, because it can be changed into another prime (2122453654187) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061226827073 + 1061226827074.
It is an arithmetic number, because the mean of its divisors is an integer number (1061226827074).
Almost surely, 22122453654147 is an apocalyptic number.
2122453654147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122453654147 is an equidigital number, since it uses as much as digits as its factorization.
2122453654147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1612800, while the sum is 46.
The spelling of 2122453654147 in words is "two trillion, one hundred twenty-two billion, four hundred fifty-three million, six hundred fifty-four thousand, one hundred forty-seven".
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