Base | Representation |
---|---|
bin | 11110111000111010110… |
… | …100010001110011001011 |
3 | 21111221001122201112110012 |
4 | 132320322310101303023 |
5 | 234234242330032042 |
6 | 4303053305142135 |
7 | 306234333425012 |
oct | 36707264216313 |
9 | 7457048645405 |
10 | 2122700627147 |
11 | 749261190071 |
12 | 2a348818a94b |
13 | 1252290c4769 |
14 | 74a4c74da79 |
15 | 3a33a0dde82 |
hex | 1ee3ad11ccb |
2122700627147 has 2 divisors, whose sum is σ = 2122700627148. Its totient is φ = 2122700627146.
The previous prime is 2122700627143. The next prime is 2122700627167. The reversal of 2122700627147 is 7417260072212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2122700627147 - 22 = 2122700627143 is a prime.
It is a super-2 number, since 2×21227006271472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2122700627143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061350313573 + 1061350313574.
It is an arithmetic number, because the mean of its divisors is an integer number (1061350313574).
Almost surely, 22122700627147 is an apocalyptic number.
2122700627147 is a deficient number, since it is larger than the sum of its proper divisors (1).
2122700627147 is an equidigital number, since it uses as much as digits as its factorization.
2122700627147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 131712, while the sum is 41.
Adding to 2122700627147 its reverse (7417260072212), we get a palindrome (9539960699359).
The spelling of 2122700627147 in words is "two trillion, one hundred twenty-two billion, seven hundred million, six hundred twenty-seven thousand, one hundred forty-seven".
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