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212298875443 is a prime number
BaseRepresentation
bin1100010110110111111…
…1111100001000110011
3202021222110210021212201
43011231333330020303
511434242003003233
6241310113404031
721223651444504
oct3055577741063
9667873707781
10212298875443
11820431a9376
123518a569617
1317034379975
14a3bd69cbab
1557c808077d
hex316dffc233

212298875443 has 2 divisors, whose sum is σ = 212298875444. Its totient is φ = 212298875442.

The previous prime is 212298875359. The next prime is 212298875449. The reversal of 212298875443 is 344578892212.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 212298875443 - 225 = 212265321011 is a prime.

It is not a weakly prime, because it can be changed into another prime (212298875449) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106149437721 + 106149437722.

It is an arithmetic number, because the mean of its divisors is an integer number (106149437722).

Almost surely, 2212298875443 is an apocalyptic number.

212298875443 is a deficient number, since it is larger than the sum of its proper divisors (1).

212298875443 is an equidigital number, since it uses as much as digits as its factorization.

212298875443 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 7741440, while the sum is 55.

The spelling of 212298875443 in words is "two hundred twelve billion, two hundred ninety-eight million, eight hundred seventy-five thousand, four hundred forty-three".