Base | Representation |
---|---|
bin | 110000010001010111111110… |
… | …000000011110011000100100 |
3 | 1000211200200220221222211000220 |
4 | 300101113332000132120210 |
5 | 210311311302200330200 |
6 | 2031305210535404340 |
7 | 62501116603325052 |
oct | 6021277600363044 |
9 | 1024620827884026 |
10 | 212300200011300 |
11 | 61711011284945 |
12 | 1b98924b5236b0 |
13 | 915ca9106983b |
14 | 3a5d55512b1d2 |
15 | 1982636ecb4a0 |
hex | c115fe01e624 |
212300200011300 has 288 divisors, whose sum is σ = 617983390531584. Its totient is φ = 56270934720000.
The previous prime is 212300200011257. The next prime is 212300200011323. The reversal of 212300200011300 is 3110002003212.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 212300200011300.
It is an unprimeable number.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 101725058857 + ... + 101725060943.
It is an arithmetic number, because the mean of its divisors is an integer number (2145775661568).
Almost surely, 2212300200011300 is an apocalyptic number.
212300200011300 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 212300200011300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (308991695265792).
212300200011300 is an abundant number, since it is smaller than the sum of its proper divisors (405683190520284).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
212300200011300 is a wasteful number, since it uses less digits than its factorization.
212300200011300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4659 (or 4652 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 212300200011300 its reverse (3110002003212), we get a palindrome (215410202014512).
The spelling of 212300200011300 in words is "two hundred twelve trillion, three hundred billion, two hundred million, eleven thousand, three hundred".
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