Base | Representation |
---|---|
bin | 11110111001001101010… |
… | …010000110011001010001 |
3 | 21111221212020200101102211 |
4 | 132321031102012121101 |
5 | 234240411132402031 |
6 | 4303144133312121 |
7 | 306245114642605 |
oct | 36711522063121 |
9 | 7457766611384 |
10 | 2123010434641 |
11 | 749400053018 |
12 | 2a3553a95641 |
13 | 1252783475c5 |
14 | 74a7b957505 |
15 | 3a3573d8bb1 |
hex | 1ee4d486651 |
2123010434641 has 2 divisors, whose sum is σ = 2123010434642. Its totient is φ = 2123010434640.
The previous prime is 2123010434621. The next prime is 2123010434651. The reversal of 2123010434641 is 1464340103212.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1575203215041 + 547807219600 = 1255071^2 + 740140^2 .
It is a cyclic number.
It is not a de Polignac number, because 2123010434641 - 217 = 2123010303569 is a prime.
It is not a weakly prime, because it can be changed into another prime (2123010434621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1061505217320 + 1061505217321.
It is an arithmetic number, because the mean of its divisors is an integer number (1061505217321).
Almost surely, 22123010434641 is an apocalyptic number.
It is an amenable number.
2123010434641 is a deficient number, since it is larger than the sum of its proper divisors (1).
2123010434641 is an equidigital number, since it uses as much as digits as its factorization.
2123010434641 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13824, while the sum is 31.
Adding to 2123010434641 its reverse (1464340103212), we get a palindrome (3587350537853).
The spelling of 2123010434641 in words is "two trillion, one hundred twenty-three billion, ten million, four hundred thirty-four thousand, six hundred forty-one".
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