Base | Representation |
---|---|
bin | 11110111001010001011… |
… | …011110111001010101111 |
3 | 21111222001002202212212200 |
4 | 132321101123313022233 |
5 | 234241032001240300 |
6 | 4303155102432543 |
7 | 306246622054245 |
oct | 36712133671257 |
9 | 7458032685780 |
10 | 2123080102575 |
11 | 749436407623 |
12 | 2a3573292753 |
13 | 1252898cac33 |
14 | 74a86cd0795 |
15 | 3a35d59b200 |
hex | 1ee516f72af |
2123080102575 has 72 divisors (see below), whose sum is σ = 3897643625616. Its totient is φ = 1104364800000.
The previous prime is 2123080102573. The next prime is 2123080102651. The reversal of 2123080102575 is 5752010803212.
2123080102575 is a `hidden beast` number, since 2 + 1 + 2 + 3 + 0 + 80 + 1 + 0 + 2 + 575 = 666.
It is not a de Polignac number, because 2123080102575 - 21 = 2123080102573 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2123080102571) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 825375 + ... + 2219775.
Almost surely, 22123080102575 is an apocalyptic number.
2123080102575 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
2123080102575 is a deficient number, since it is larger than the sum of its proper divisors (1774563523041).
2123080102575 is a wasteful number, since it uses less digits than its factorization.
2123080102575 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1394585 (or 1394577 counting only the distinct ones).
The product of its (nonzero) digits is 33600, while the sum is 36.
Adding to 2123080102575 its reverse (5752010803212), we get a palindrome (7875090905787).
The spelling of 2123080102575 in words is "two trillion, one hundred twenty-three billion, eighty million, one hundred two thousand, five hundred seventy-five".
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