Base | Representation |
---|---|
bin | 1100010110111010101… |
… | …1111010110000101111 |
3 | 202022000021111000021121 |
4 | 3011232223322300233 |
5 | 11434302430413033 |
6 | 241311204441411 |
7 | 21224151442045 |
oct | 3055653726057 |
9 | 668007430247 |
10 | 212310404143 |
11 | 82049763022 |
12 | 351923a9267 |
13 | 17036885296 |
14 | a3c1020395 |
15 | 57c90ab62d |
hex | 316eafac2f |
212310404143 has 12 divisors (see below), whose sum is σ = 224256435408. Its totient is φ = 200971293120.
The previous prime is 212310404113. The next prime is 212310404161. The reversal of 212310404143 is 341404013212.
It is not a de Polignac number, because 212310404143 - 213 = 212310395951 is a prime.
It is a super-3 number, since 3×2123104041433 (a number of 35 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (212310404113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 201063 + ... + 681943.
It is an arithmetic number, because the mean of its divisors is an integer number (18688036284).
Almost surely, 2212310404143 is an apocalyptic number.
212310404143 is a deficient number, since it is larger than the sum of its proper divisors (11946031265).
212310404143 is a wasteful number, since it uses less digits than its factorization.
212310404143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 482142 (or 482123 counting only the distinct ones).
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 212310404143 its reverse (341404013212), we get a palindrome (553714417355).
The spelling of 212310404143 in words is "two hundred twelve billion, three hundred ten million, four hundred four thousand, one hundred forty-three".
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