Base | Representation |
---|---|
bin | 110000010001100010001000… |
… | …010010110100110011001011 |
3 | 1000211201202002022002021120212 |
4 | 300101202020102310303023 |
5 | 210312001123130341412 |
6 | 2031314213310511335 |
7 | 62501654140650431 |
oct | 6021421022646313 |
9 | 1024652068067525 |
10 | 212311110012107 |
11 | 617156aa731a37 |
12 | 1b98b39520554b |
13 | 9160b0c442712 |
14 | 3a5dcac090d51 |
15 | 1982a74bde222 |
hex | c118884b4ccb |
212311110012107 has 2 divisors, whose sum is σ = 212311110012108. Its totient is φ = 212311110012106.
The previous prime is 212311110012103. The next prime is 212311110012173. The reversal of 212311110012107 is 701210011113212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212311110012107 - 22 = 212311110012103 is a prime.
It is not a weakly prime, because it can be changed into another prime (212311110012103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106155555006053 + 106155555006054.
It is an arithmetic number, because the mean of its divisors is an integer number (106155555006054).
Almost surely, 2212311110012107 is an apocalyptic number.
212311110012107 is a deficient number, since it is larger than the sum of its proper divisors (1).
212311110012107 is an equidigital number, since it uses as much as digits as its factorization.
212311110012107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 168, while the sum is 23.
Adding to 212311110012107 its reverse (701210011113212), we get a palindrome (913521121125319).
The spelling of 212311110012107 in words is "two hundred twelve trillion, three hundred eleven billion, one hundred ten million, twelve thousand, one hundred seven".
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