Base | Representation |
---|---|
bin | 110000010001111110000101… |
… | …001111001100110001011011 |
3 | 1000211211121112222202111110001 |
4 | 300101332011033030301123 |
5 | 210312444110104014042 |
6 | 2031340055424033431 |
7 | 62504065663260064 |
oct | 6021760517146133 |
9 | 1024747488674401 |
10 | 212341123501147 |
11 | 61727401549533 |
12 | 1b995170762877 |
13 | 91638b354b4a4 |
14 | 3a6151820b56b |
15 | 198372eacebb7 |
hex | c11f853ccc5b |
212341123501147 has 2 divisors, whose sum is σ = 212341123501148. Its totient is φ = 212341123501146.
The previous prime is 212341123501063. The next prime is 212341123501153. The reversal of 212341123501147 is 741105321143212.
212341123501147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212341123501147 - 215 = 212341123468379 is a prime.
It is not a weakly prime, because it can be changed into another prime (212341123501847) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106170561750573 + 106170561750574.
It is an arithmetic number, because the mean of its divisors is an integer number (106170561750574).
Almost surely, 2212341123501147 is an apocalyptic number.
212341123501147 is a deficient number, since it is larger than the sum of its proper divisors (1).
212341123501147 is an equidigital number, since it uses as much as digits as its factorization.
212341123501147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40320, while the sum is 37.
Adding to 212341123501147 its reverse (741105321143212), we get a palindrome (953446444644359).
The spelling of 212341123501147 in words is "two hundred twelve trillion, three hundred forty-one billion, one hundred twenty-three million, five hundred one thousand, one hundred forty-seven".
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