21241144114213 has 4 divisors (see below), whose sum is σ = 21396188961900. Its totient is φ = 21086099266528.

The previous prime is 21241144114199. The next prime is 21241144114259. The reversal of 21241144114213 is 31241144114212.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5552399460609 + 15688744653604 = 2356353^2 + 3960902^2 .

It is a cyclic number.

It is not a de Polignac number, because 21241144114213 - 2²¹ = 21241142017061 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21241144114313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77522423638 + ... + 77522423911.

It is an arithmetic number, because the mean of its divisors is an integer number (5349047240475).

Almost surely, 2^{21241144114213} is an apocalyptic number.

It is an amenable number.

21241144114213 is a deficient number, since it is larger than the sum of its proper divisors (155044847687).

21241144114213 is a wasteful number, since it uses less digits than its factorization.

21241144114213 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155044847686.

The product of its digits is 6144, while the sum is 31.

Adding to 21241144114213 its reverse (31241144114212), we get a palindrome (52482288228425).

Subtracting 21241144114213 from its reverse (31241144114212), we obtain a palindrome (9999999999999).

The spelling of 21241144114213 in words is "twenty-one trillion, two hundred forty-one billion, one hundred forty-four million, one hundred fourteen thousand, two hundred thirteen".