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212415000233 is a prime number
BaseRepresentation
bin1100010111010011101…
…0111010111010101001
3202022021120022001010212
43011310322322322221
511440011220001413
6241325422350505
721226561465652
oct3056472727251
9668246261125
10212415000233
11820a2803677
123520142b435
1317052447a67
14a3d0c8a529
1557d336cca8
hex3174ebaea9

212415000233 has 2 divisors, whose sum is σ = 212415000234. Its totient is φ = 212415000232.

The previous prime is 212415000167. The next prime is 212415000247. The reversal of 212415000233 is 332000514212.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135182699584 + 77232300649 = 367672^2 + 277907^2 .

It is a cyclic number.

It is not a de Polignac number, because 212415000233 - 214 = 212414983849 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 212415000199 and 212415000208.

It is not a weakly prime, because it can be changed into another prime (212415000533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106207500116 + 106207500117.

It is an arithmetic number, because the mean of its divisors is an integer number (106207500117).

Almost surely, 2212415000233 is an apocalyptic number.

It is an amenable number.

212415000233 is a deficient number, since it is larger than the sum of its proper divisors (1).

212415000233 is an equidigital number, since it uses as much as digits as its factorization.

212415000233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

Adding to 212415000233 its reverse (332000514212), we get a palindrome (544415514445).

The spelling of 212415000233 in words is "two hundred twelve billion, four hundred fifteen million, two hundred thirty-three", and thus it is an aban number.