Base | Representation |
---|---|
bin | 1100010111010011101… |
… | …0111010111010111011 |
3 | 202022021120022001011112 |
4 | 3011310322322322323 |
5 | 11440011220002001 |
6 | 241325422350535 |
7 | 21226561466006 |
oct | 3056472727273 |
9 | 668246261145 |
10 | 212415000251 |
11 | 820a2803693 |
12 | 3520142b44b |
13 | 17052447a7c |
14 | a3d0c8a53d |
15 | 57d336ccbb |
hex | 3174ebaebb |
212415000251 has 2 divisors, whose sum is σ = 212415000252. Its totient is φ = 212415000250.
The previous prime is 212415000247. The next prime is 212415000319. The reversal of 212415000251 is 152000514212.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 212415000251 - 22 = 212415000247 is a prime.
It is not a weakly prime, because it can be changed into another prime (212415000451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106207500125 + 106207500126.
It is an arithmetic number, because the mean of its divisors is an integer number (106207500126).
Almost surely, 2212415000251 is an apocalyptic number.
212415000251 is a deficient number, since it is larger than the sum of its proper divisors (1).
212415000251 is an equidigital number, since it uses as much as digits as its factorization.
212415000251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 800, while the sum is 23.
Adding to 212415000251 its reverse (152000514212), we get a palindrome (364415514463).
The spelling of 212415000251 in words is "two hundred twelve billion, four hundred fifteen million, two hundred fifty-one", and thus it is an aban number.
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