Base | Representation |
---|---|
bin | 10011110010001000… |
… | …111111001010100111 |
3 | 2000211102011020000200 |
4 | 103302020333022213 |
5 | 322001012430320 |
6 | 13431504241543 |
7 | 1351255444560 |
oct | 236210771247 |
9 | 60742136020 |
10 | 21242311335 |
11 | 9010804a03 |
12 | 414a0102b3 |
13 | 2006b949bb |
14 | 10572ab167 |
15 | 844d63290 |
hex | 4f223f2a7 |
21242311335 has 24 divisors (see below), whose sum is σ = 42080007840. Its totient is φ = 9710770752.
The previous prime is 21242311333. The next prime is 21242311339. The reversal of 21242311335 is 53311324212.
21242311335 is a `hidden beast` number, since 2 + 12 + 4 + 2 + 311 + 335 = 666.
It is not a de Polignac number, because 21242311335 - 21 = 21242311333 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 21242311299 and 21242311308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21242311333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 33717640 + ... + 33718269.
It is an arithmetic number, because the mean of its divisors is an integer number (1753333660).
Almost surely, 221242311335 is an apocalyptic number.
21242311335 is a deficient number, since it is larger than the sum of its proper divisors (20837696505).
21242311335 is a wasteful number, since it uses less digits than its factorization.
21242311335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67435927 (or 67435924 counting only the distinct ones).
The product of its digits is 4320, while the sum is 27.
Adding to 21242311335 its reverse (53311324212), we get a palindrome (74553635547).
The spelling of 21242311335 in words is "twenty-one billion, two hundred forty-two million, three hundred eleven thousand, three hundred thirty-five".
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