Base | Representation |
---|---|
bin | 1100010111011010101… |
… | …0010100000001111011 |
3 | 202022100121020121011211 |
4 | 3011312222110001323 |
5 | 11440041203413313 |
6 | 241332344303551 |
7 | 21230364625432 |
oct | 3056652240173 |
9 | 668317217154 |
10 | 212444201083 |
11 | 82108238704 |
12 | 3520b171bb7 |
13 | 1705850007a |
14 | a3d4acc119 |
15 | 57d5bd9e3d |
hex | 3176a9407b |
212444201083 has 2 divisors, whose sum is σ = 212444201084. Its totient is φ = 212444201082.
The previous prime is 212444201059. The next prime is 212444201093. The reversal of 212444201083 is 380102444212.
212444201083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 212444201083 - 25 = 212444201051 is a prime.
It is not a weakly prime, because it can be changed into another prime (212444201093) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106222100541 + 106222100542.
It is an arithmetic number, because the mean of its divisors is an integer number (106222100542).
Almost surely, 2212444201083 is an apocalyptic number.
212444201083 is a deficient number, since it is larger than the sum of its proper divisors (1).
212444201083 is an equidigital number, since it uses as much as digits as its factorization.
212444201083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 212444201083 its reverse (380102444212), we get a palindrome (592546645295).
The spelling of 212444201083 in words is "two hundred twelve billion, four hundred forty-four million, two hundred one thousand, eighty-three".
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