Base | Representation |
---|---|
bin | 1100010111111011001… |
… | …0111101000100010001 |
3 | 202022201010001122121111 |
4 | 3011332302331010101 |
5 | 11440331123342144 |
6 | 241354101453321 |
7 | 21233643000106 |
oct | 3057662750421 |
9 | 668633048544 |
10 | 212580684049 |
11 | 82178288348 |
12 | 35248a11241 |
13 | 1707a878616 |
14 | a408c98aad |
15 | 57e2b99534 |
hex | 317ecbd111 |
212580684049 has 2 divisors, whose sum is σ = 212580684050. Its totient is φ = 212580684048.
The previous prime is 212580684037. The next prime is 212580684079. The reversal of 212580684049 is 940486085212.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 151772576400 + 60808107649 = 389580^2 + 246593^2 .
It is a cyclic number.
It is not a de Polignac number, because 212580684049 - 219 = 212580159761 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 212580683993 and 212580684011.
It is not a weakly prime, because it can be changed into another prime (212580684079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106290342024 + 106290342025.
It is an arithmetic number, because the mean of its divisors is an integer number (106290342025).
Almost surely, 2212580684049 is an apocalyptic number.
It is an amenable number.
212580684049 is a deficient number, since it is larger than the sum of its proper divisors (1).
212580684049 is an equidigital number, since it uses as much as digits as its factorization.
212580684049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1105920, while the sum is 49.
The spelling of 212580684049 in words is "two hundred twelve billion, five hundred eighty million, six hundred eighty-four thousand, forty-nine".
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