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21300040111 = 75951573947
BaseRepresentation
bin10011110101100101…
…001101000110101111
32000222102210011000111
4103311211031012233
5322110302240421
613441325440451
71352556232210
oct236545150657
960872704014
1021300040111
119040354439
124165410127
132015b27c3c
141060c17407
15849e67ee1
hex4f594d1af

21300040111 has 8 divisors (see below), whose sum is σ = 24755495040. Its totient is φ = 17947733208.

The previous prime is 21300040103. The next prime is 21300040183. The reversal of 21300040111 is 11104000312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21300040111 - 23 = 21300040103 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 21300040091 and 21300040100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21300040211) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25786561 + ... + 25787386.

It is an arithmetic number, because the mean of its divisors is an integer number (3094436880).

Almost surely, 221300040111 is an apocalyptic number.

21300040111 is a deficient number, since it is larger than the sum of its proper divisors (3455454929).

21300040111 is an equidigital number, since it uses as much as digits as its factorization.

21300040111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51574013.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 21300040111 its reverse (11104000312), we get a palindrome (32404040423).

The spelling of 21300040111 in words is "twenty-one billion, three hundred million, forty thousand, one hundred eleven".

Divisors: 1 7 59 413 51573947 361017629 3042862873 21300040111