Base | Representation |
---|---|
bin | 11110111111101111010… |
… | …010100010111001100011 |
3 | 21112121221222212100022212 |
4 | 132333233102202321203 |
5 | 234344241444141213 |
6 | 4310304054152335 |
7 | 306613652255504 |
oct | 36775722427143 |
9 | 7477858770285 |
10 | 2130023427683 |
11 | 751379771538 |
12 | 2a49906526ab |
13 | 125b2524c528 |
14 | 751450d6bab |
15 | 3a617e1c9a8 |
hex | 1efef4a2e63 |
2130023427683 has 2 divisors, whose sum is σ = 2130023427684. Its totient is φ = 2130023427682.
The previous prime is 2130023427661. The next prime is 2130023427689. The reversal of 2130023427683 is 3867243200312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2130023427683 - 230 = 2128949685859 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 2130023427683.
It is not a weakly prime, because it can be changed into another prime (2130023427689) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065011713841 + 1065011713842.
It is an arithmetic number, because the mean of its divisors is an integer number (1065011713842).
Almost surely, 22130023427683 is an apocalyptic number.
2130023427683 is a deficient number, since it is larger than the sum of its proper divisors (1).
2130023427683 is an equidigital number, since it uses as much as digits as its factorization.
2130023427683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 290304, while the sum is 41.
Adding to 2130023427683 its reverse (3867243200312), we get a palindrome (5997266627995).
The spelling of 2130023427683 in words is "two trillion, one hundred thirty billion, twenty-three million, four hundred twenty-seven thousand, six hundred eighty-three".
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